Given: Circle k(O), diameter US , m RU=50°, m UT=30° Find: m∠RUS, m∠STU

Answer:
[tex]\boxed{m<RUS = 65 \ degrees}\\\boxed{m<STU = 90 \ degrees}[/tex]
Step-by-step explanation:
Given that RU = 50°, So Central Angle ROU = 50° too because the measure of arc is equal to its central angle
Now, Let's assume a triangle ROU. It is an isosceles triangle since RO = RU (Radii of the same circle)
So,
∠ORU ≅ ∠OUR (Angles opposite to equal sides are equal)
So, we can write them as 2(∠RUO)
So,
2(∠RUO)+50 = 180 (Interior angles of a triangle add up to 180)
2(∠RUO) = 180-50
2(∠RUO) = 130
Dividing both sides by 2
∠RUO = 130/2
∠RUO = 65 degrees
m∠RUS = 65 degrees (Both are the same)
In a semi circle (Given that SU is a diameter) , there must be a 90 degrees angle sin it opposite to the diameter.
So,
m∠STU = 90 degrees
From the diagram of circle k(O), m∠RUS = 65° and m∠STU = 90°
Given that:
m∠ORU = m∠OUR (isosceles triangle)
m∠ORU + m∠OUR + m∠ROU = 180° (angle in triangle)
50 + 2 * m∠OUR = 180
m∠OUR = 65°
m∠OUR = m∠RUS = 65°
m∠STU = 90° (angle subtended at circumference by semicircle).
From the diagram of circle k(O), m∠RUS = 65° and m∠STU = 90°
Find out more on circle theorems at: https://brainly.com/question/17023621