Question

Will mark BRAINLIST Find the perimeter of the following shape, rounded to the nearest tenth: coordinate plane with quadrilateral ABCD at A negative 3 comma 2, B negative 1 comma 0, C negative 3 comma negative 2, and D negative 5 comma 0 8 11.3 12 17.9

Answer 1

Answer:

11.3 units

Step-by-step explanation:

Let's find the length of one of the boxes.

$a^2+b^2=c^2\\1^2+1^2=c^2\\1+1=c^2\\2 = c^2\\\\\sqrt{2} = c\\ c = 1.414...$

Let's simplify c down to 1.41.

Now, there are 8 of these little boxes for the perimeter, let's multiply.

$1.41\cdot8=11.28$

That can be simplified to the nearest tenth - 11.3

Hope this helped!

Answer 2

The perimeter of the box is 11.31 units if the coordinate plane with quadrilateral ABCD at A negative 3 comma 2, B negative 1 comma 0, C negative 3 comma negative 2, and D negative 5 comma 0

What is a cube?

It is defined as three-dimensional geometry that has six square faces and eight vertices.

We have coordinates of the box:

A: (-3, 2)

B: (-1, 0)

C: (-3, -2)

D: (-5, 0)

We can find the lengths between A and B and so on with the help of distance formula:

$\rm d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Lengths:

AB = √(8)

BC = √(8)

CD = √(8)

DA = √(8)

Perimeter = sum of all lengths

= √(8) +√(8)+√(8)+√(8)

= 11.31

Thus, the perimeter of the box is 11.31 units if the coordinate plane with quadrilateral ABCD at A negative 3 comma 2, B negative 1 comma 0, C negative 3 comma negative 2, and D negative 5 comma 0

Learn more about the cube here:

brainly.com/question/15420947

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