Question

On the coordinate plane below, Point P, is located at (2,-3) and point Q is located at (-4,4). Find the distance between points, P and Q

Answer 1

Answer:

$d = \sqrt{85}$ or d ≈ 9.22

Step-by-step explanation:

Distance formula:

$d = \sqrt{(2 - (-4))^2 + (-3- 4)^2} \\d = \sqrt{36+ 49}\\d = \sqrt{85}$