Question

Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win

Answer 1

Answer: $\dfrac{1}{3}$

Step-by-step explanation:

Given: Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items.

Rock beats Scissors, Scissors beat Paper, and Paper beats Rock.

We assume that both Jim and Renee have an equal chance of choosing any one of the hand signs.

Since, there are 3 possibilities, either Jim win or Renee or its a tie.

So, the probability that Jim will win: $\dfrac{\text{Outcomes for Jim to win}}{\text{Total outcomes}}$

$=\dfrac{1}{3}$

Hence, the required probability is $\dfrac{1}{3}$ .