Answer:
The gap between the plates will be 1.2 x 10^-15 m
No, this is not practically achievable.
Explanation:
Capacitance = 1.0 F
area of plate = 1.4 cm^2 = 1.4/10000 m^2 = m^2
distance = ?
We use the equation
[tex]C[/tex] = [tex]\frac{A}{d}[/tex]*ε
C is the capacitance
where A is the area
d is the distance of separation of plates
ε is the permeability of free space = 8.854×10^-12 F⋅m−1
substituting values, we have
1 = [tex]\frac{0.00014}{d}[/tex]* 8.854×10^-12
distance between plates = 1.2 x 10^-15 m
This is not practically achievable in real life