Answer:
1.9cm
Step-by-step explanation:
The density d of a material is related to its mass m and volume V as follows;
d = [tex]\frac{m}{V}[/tex] ------------------(i)
The material in question here is the lead ball.
Now, from known experiment;
the density of lead is 11.34g/cm³
From the question, the weight/mass of the lead ball is 326g
Substitute these values into equation (i) as follows;
11.34 = [tex]\frac{326}{V}[/tex]
V = [tex]\frac{326}{11.34}[/tex]
V = 28.75cm³
Now, since the ball is of course spherical, we can get the radius by using the following relation from the volume of a sphere;
V = [tex]\frac{4}{3} \pi r^3[/tex] [V = volume, r = radius]
V = 28.75cm³
=> 28.75 = [tex]\frac{4}{3} \pi r^3[/tex]
=> 3 x 28.75 = 4 π r³
=> 86.25 = 4 π r³
=> 21.5625 = π r³ [Take π = 3.142]
=> 21.5625 = (3.142) r³ [divide both sides by 3.142]
=> 6.86 = r³ [Take the cube root of both sides]
=> ∛6.86 = ∛r³
=> 1.90 = r
Therefore, the radius is 1.9cm to the nearest tenth
