Question

HELP PLEASE ASAP 20 points

Answer 1

Answer:

Its d $x^{2} -6x+7=0$

Step-by-step explanation:

A= $2+\sqrt{3\\}$

B= $3\sqrt{2}$

C= $-3+\sqrt{2}$

Answer 2

Answer:

D. x^2 - 6x + 7 = 0.

Step-by-step explanation:

The roots are 3 plus or minus sqrt(2). That means the equation is...

(x - [3 + sqrt(2)]) * (x - [3 - sqrt(2)])

= [x - 3 - sqrt(2)] * [x - 3 + sqrt(2)]

= x^2 - 3x - xsqrt(2) - 3x + 9 + 3sqrt(2) + xsqrt(2) - 3sqrt(2) - (sqrt(2))^2

= x^2 - 3x - 3x + 9 - 2 - xsqrt(2) + xsqrt(2) + 3sqrt(2) - 3sqrt(2)

= x^2 - 6x + 7.

Hope this helps!