Answer:
x-intercept → (-5, 0)
Step-by-step explanation:
Let the equation of the line having pairs given in the table is,
y - y' = m(x - x')
m = slope of the line
(x', y') is a point lying on the line.
From the given table,
Two points (33, -22) and (52, -33) lie on the line.
Slope of the line = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m = [tex]\frac{-33+22}{52-33}[/tex]
m = [tex]-\frac{11}{19}[/tex]
Equation of the line passing through (33, -22) and slope = [tex]-\frac{11}{19}[/tex] will be,
y + 22 = [tex]-\frac{11}{19}(x - 33)[/tex]
For x-intercept y = 0,
0 + 22 = [tex]-\frac{11}{19}(x-33)[/tex]
-38 = x - 33
x = -38 + 33
x = -5
Therefore, x-intercept of the line is (-5, 0).
