Which could be the areas of the smaller squares?


Answer:
Step-by-step explanation:
We have a right triangle. Therefore, we can use the Pythagorean theorem:
The sum of the areas of the squares built on the legs is equal to the area of the square built on the hypotenuse.
We have the area of the largest square (the square built on the hypotenuse).
A₃ = 36 u²
From the Pythagorean therem we have the equation:
A₃ = A₁ + A₂
We need the areas of the smaller squares (A₁ and A₂).
A₁ + A₂ = 36.
From the second picture, we have:
A) 6 and 30 → 6 + 30 = 3 CORRECT
B) 8 and 28 → 8 + 28 = 36 CORRECT
C) 4 and 16 → 4 + 16 = 20 ≠ 36 INCORRECT