Answer:
Option (B)
Step-by-step explanation:
There are two lines on the graph representing the system of equations.
First line passes through two points (-3, 1) and (-2, 3).
Slope of the line = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{3-1}{-2+3}[/tex]
m = 2
Equation of the line passing through (x', y') and slope = m is,
y - y' = m(x - x')
Equation of the line passing through (-3, 1) and slope = 2 will be,
y - 1 = 2(x + 3)
y = 2x + 7 ----------(1)
Second line passes through (0, 1) and (-1, 4) and y-intercept 'b' of the line is 1.
Let the equation of this line is,
y = mx + b
Slope 'm' = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{4-1}{-1-0}[/tex]
= -3
Here 'b' = 1
Therefore, equation of the line will be,
y = -3x + 1 ---------(2)
From equation (1) and (2),
2x + 7 = -3x + 1
5x = -6
x = [tex]-\frac{6}{5}[/tex]
x = [tex]-1\frac{1}{5}[/tex]
From equation (1),
y = 2x + 7
y = [tex]-\frac{12}{5}+7[/tex]
= [tex]\frac{-12+35}{5}[/tex]
= [tex]\frac{23}{5}[/tex]
= [tex]4\frac{3}{5}[/tex]
Therefore, exact solution of the system of equations is [tex](-1\frac{1}{5},4\frac{3}{5})[/tex].
Option (B) will be the answer.
