Lengths of pregnancies​ (in humans) have a mean of 267.6 days and a standard deviation of 15.4 days. A woman tracked her pregnancy and found it to be 309 days. Find the z score for 309 days. Is such a length​ unusual?

Respuesta :

Answer:

The z-score is  [tex]z = 2.65[/tex]

The length of days is not unusual

Step-by-step explanation:

From the question we are told that

     The population mean is  [tex]\mu = 267.6 \ days[/tex]

     The standard deviation is  [tex]\sigma = 15.4 \ days[/tex]

      The value considered is  [tex]x = 309 \ days[/tex]

The z-score is mathematically represented as

           [tex]z = \frac{x - \mu}{\sigma }[/tex]

            [tex]z = \frac{309 - 267.6}{15.6 }[/tex]

           [tex]z = 2.65[/tex]

Now given that the z-score is not greater than 3  then we can say that the length of days is not unusual

(reference khan academy)

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