Question

Please help asap Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bubble gum nested at the bottom of the cone. The radius of the snow cone is 4 inches, and the height of the cone is 6 inches. If the diameter of the bubble gum is 0.8 inches, which of the following can be used to calculate the volume of the cone that can be filled with flavored ice? 1 over 3(3.14)(62)(4) − 4 over 3(3.14)(0.43) 1 over 3(3.14)(42)(6) − 4 over 3(3.14)(0.43) 1 over 3(3.14)(62)(4) − 4 over 3(3.14)(0.83) 1 over 3(3.14)(42)(6) − 4 over 3(3.14)(0.83)

Answer 1

Answer:

1/3 pi (6)^2 *10 - 4/3 pi (.75)^3

Step-by-step explanation:

Find the volume of the cone without the bubble gum

The radius is 6 inches and the height is 10

V =1/3 pi r^2 h

V = 1/3 pi (6)^2 *10

Now find the volume of the sphere with the bubble gum

The diameter is 1.5 inches

That means the radius is 1.5/2 = .75

V =4/3 pi r^3 h

V = 4/3 pi (.75)^3

Answer 2

The expression which is used to calculate the volume of the Snowy's Snow Cones that can be filled with flavored ice is 1 over 3(3.14)(42)(6) − 4 over 3(3.14)(0.83).

What is of volume of cone?

Volume of cone is the amount of quantity, which is obtained it in the 3 dimensional space.

The volume of the cone can be given as,

$V=\dfrac{1}{3}\pi r^2h$

Here, (r) is the radius of the base of the cone and (h) is the height of the cone.

Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bubble gum nested at the bottom of the cone.

The radius of the snow cone is 4 inches, and the height of the cone is 6 inches. The volume of this snow cone is,

$V_c=\dfrac{1}{3}\pi r^2h\\V_c=\dfrac{1}{3}(3.14)(4)^2(6)$

The volume of the sphere can be calculated with the following formula.

$V=\dfrac{4}{3}\pi r^3$

Here, r is the radius of the sphere. The diameter of the bubble gum is 0.8 inches. Thus, the radius of it is 0.4 inches (half of diameter). The volume of it is,

$V_s=\dfrac{4}{3}\pi (0.8)^3\\V_s=\dfrac{4}{3}(3.14)(0.8)^3$

The volume of remaining cone is,

$V=V_c-V_s\\V=\dfrac{1}{3}(3.14)(4)^2(6)-\dfrac{4}{3}(3.14)(0.8)^3$

Thus, the expression which is used to calculate the volume of the Snowy's Snow Cones that can be filled with flavored ice is 1 over 3(3.14)(42)(6) − 4 over 3(3.14)(0.83).

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