Question

Determine the equation of the line that is parallel to y=2÷3x+4 and passes through the point (3,7).

Answer 1

Answer:

y=(2/3)x+15

Step-by-step explanation:

y=(2/3)x+4

comparing to y=mx+c

m=2/3

since they are parallel they have the same gradient so we continue to find the equation using y-y1=m(x-x1)

y1=7 x1=3

y-7=(2/3)(x-3)

3(y-7)=2(x-3)

3y-21=2x-6

3y=2x-6+21

3y=2x+15

y=(2/3)x+(15/3)

y=(2/3)x+5