Question

Find the area of the triangle

Answer 1

Answer:

$Area = 24.8 cm^2$

Step-by-step explanation:

Given

$PQ = 4.9cm$

$RQ = 11 cm$

$<Q = 113\ degrees$

Required

Find the area of the triangle

When presented with a triangle where two sides are known and an angle between the two sides; The area is solved as follows;

$Area = \frac{1}{2}ABSinC$

Where A and B are the two known sides and C is the angle between A and B

Having said that;

The area of the triangle is calculated as thus;

$Area = \frac{1}{2} * RQ * PQ * SinQ$

$Area = \frac{1}{2} * 11 * 4.9 * Sin113$

$Sin113 = 0.9205$

Hence, the equation becomes

$Area = \frac{1}{2} * 11 * 4.9 * 0.9205$

$Area = \frac{11 * 4.9 * 0.9205}{2}$

$Area = \frac{49.6152}{2}$

$Area = 24.8076$

$Area = 24.8 cm^2$ --- Approximated