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what is the distance between the points (4, 5) and (10, 13) on a coordinte plane a. 12 units b. 8 units c. 10 units d. 14 units

Respuesta :

Answer:

10 units

Option C is the correct option

Step-by-step explanation:

Let the points be A and B

A ( 4 , 5 ) ------> ( x1 , y1 )

B ( 10 , 13 ) ------> ( x2 , y2 )

Now, let's find the distance between these points:

[tex] \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]

plug the values

[tex] = \: \sqrt{(10 - 4) ^{2} + {(13 - 5)}^{2} } [/tex]

Calculate the difference

[tex] = \sqrt{ {(6)}^{2} + {(8)}^{2} } [/tex]

Evaluate the power

[tex] = \sqrt{36 + 64} [/tex]

Add the numbers

[tex] = \sqrt{100} [/tex]

Write the number in exponential form with. base of 10

[tex] = \sqrt{ {(10)}^{2} } [/tex]

Reduce the index of the radical and exponent with 2

[tex] = 10 \: units[/tex]

Hope this helps..

Best regards!!

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