Question

Please help! I got 14 but it says it's incorrect! Find the maximum number of real zeros of the polynomial. f(x)=2x^(6)-3x^(3)+1-2x^(5)

Answer 1

Answer:

There are two or zero positive solutions and zero negative roots (zeros).

Step-by-step explanation:

Use Descartes' Rule of Signs to determine the number of real zeros of $f(x)=2x^6-3x^3+1-2x^5$

$f(x)=2x^6-2x^5-3x^3+1$