Respuesta :
Answer:
[tex]( \frac{13}{2} \:, - \frac{9}{2} )[/tex]
Step-by-step explanation:
[tex]5x + y = 28[/tex]
[tex]x + y = 8[/tex]
Solve the equation for y by moving 'x' to R.H.S and changing its sign
[tex]5x + y = 28[/tex]
[tex]y = 2 - x[/tex]
Substitute the given value of y into the equation 5x + y = 28
[tex]5x + 2 - x = 28[/tex]
Solve the equation for x
Collect like terms
[tex]4x + 2 = 28[/tex]
Move constant to R.H.S and change its sign
[tex]4x = 28 - 2[/tex]
Subtract the numbers
[tex]4x = 26[/tex]
Divide both sides of the equation by 4
[tex] \frac{4x}{4} = \frac{26}{4} [/tex]
Calculate
[tex]x = \frac{26}{4} [/tex]
Reduce the numbers with 2
[tex]x = \frac{13}{2} [/tex]
Now, substitute the given value of x into the equation y = 2 - x
[tex]y = 2 - \frac{13}{2} [/tex]
Solve the equation for y
[tex]y = - \frac{9}{2} [/tex]
The possible solution of the system is the ordered pair ( x , y )
[tex](x \: y) = ( \frac{13}{2} , \: - \frac{9}{2} )[/tex]
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Let's check if the given ordered pair is the solution of the system of equation:
plug the value of x and y in both equation
[tex]5 \times \frac{13}{2} - \frac{9}{2} = 28[/tex]
[tex] \frac{13}{2} - \frac{9}{2} = 2[/tex]
Simplify the equalities
[tex]28 = 28[/tex]
[tex]2 = 2[/tex]
Since , all of the equalities are true, the ordered pair is the solution of the system.
[tex](x \:, y \: ) = ( \frac{13}{2} \: , - \frac{9}{2}) [/tex]
Hope this helps....
Best regards!!
Answer:
[tex]\boxed{x=6.5} \\ \boxed{y=-4.5}[/tex]
Step-by-step explanation:
5x + y = 28
x + y = 2
Subtract both equations. (eliminating y variable)
4x + 0 = 26
4x = 26
Divide both sides by 4.
x = [tex]\frac{26}{4}[/tex]
x = 6.5
Plug x as 6.5 in the second equation and solve for y.
6.5 + y = 2
Subtract 6.5 on both sides.
6.5 - 6.5 + y = 2 - 6.5
y = -4.5