Respuesta :

Answer:

[tex]( \frac{13}{2} \:, - \frac{9}{2} )[/tex]

Step-by-step explanation:

[tex]5x + y = 28[/tex]

[tex]x + y = 8[/tex]

Solve the equation for y by moving 'x' to R.H.S and changing its sign

[tex]5x + y = 28[/tex]

[tex]y = 2 - x[/tex]

Substitute the given value of y into the equation 5x + y = 28

[tex]5x + 2 - x = 28[/tex]

Solve the equation for x

Collect like terms

[tex]4x + 2 = 28[/tex]

Move constant to R.H.S and change its sign

[tex]4x = 28 - 2[/tex]

Subtract the numbers

[tex]4x = 26[/tex]

Divide both sides of the equation by 4

[tex] \frac{4x}{4} = \frac{26}{4} [/tex]

Calculate

[tex]x = \frac{26}{4} [/tex]

Reduce the numbers with 2

[tex]x = \frac{13}{2} [/tex]

Now, substitute the given value of x into the equation y = 2 - x

[tex]y = 2 - \frac{13}{2} [/tex]

Solve the equation for y

[tex]y = - \frac{9}{2} [/tex]

The possible solution of the system is the ordered pair ( x , y )

[tex](x \: y) = ( \frac{13}{2} , \: - \frac{9}{2} )[/tex]

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Let's check if the given ordered pair is the solution of the system of equation:

plug the value of x and y in both equation

[tex]5 \times \frac{13}{2} - \frac{9}{2} = 28[/tex]

[tex] \frac{13}{2} - \frac{9}{2} = 2[/tex]

Simplify the equalities

[tex]28 = 28[/tex]

[tex]2 = 2[/tex]

Since , all of the equalities are true, the ordered pair is the solution of the system.

[tex](x \:, y \: ) = ( \frac{13}{2} \: , - \frac{9}{2}) [/tex]

Hope this helps....

Best regards!!

Answer:

[tex]\boxed{x=6.5} \\ \boxed{y=-4.5}[/tex]

Step-by-step explanation:

5x + y = 28

x + y = 2

Subtract both equations. (eliminating y variable)

4x + 0 = 26

4x = 26

Divide both sides by 4.

x = [tex]\frac{26}{4}[/tex]

x = 6.5

Plug x as 6.5 in the second equation and solve for y.

6.5 + y = 2

Subtract 6.5 on both sides.

6.5 - 6.5 + y = 2 - 6.5

y = -4.5

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