If you're good at trigonometry please help meeee

On a 30-60 set square, the side opposite the 60 degree angle is 80mm long. Find the length of the longest side to the nearest millimetre

If youre good at trigonometry please help meeee On a 3060 set square the side opposite the 60 degree angle is 80mm long Find the length of the longest side to t class=

Respuesta :

Answer:

[tex]\boxed{92 \: \mathrm{mm}}[/tex]

Step-by-step explanation:

sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

sin (60) = [tex]\frac{80}{x}[/tex]

x = [tex]\frac{80}{\mathrm{sin} (60)}[/tex]

x = 92.37604307...

x ≈ 92

Using the base dimension and either given angle you can solve for x

Sin(angle) = opposite leg/ hypotenuse

Sin(60) = 80/x

X = 80/sin(60)

X = 80/ sqrt(3)/2

X = 160/3 x sqrt(3). (This is exact answer)

For a decimal answer: 160/3 = 53 1/3

Multiplied by sqrt(3) = 92.376 mm

Rounded to nearest mm = 92

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