Question

A coin is tossed and an eight​-sided die numbered 1 through 8 is rolled. Find the probability of tossing a head and then rolling a number greater than 2. The probability of tossing a head and then rolling a number greater than 2 is nothing. ​(Round to three decimal places as​ needed.)

Answer 1

Answer:

7 out of 8

Step-by-step explanation:

heads gets tossed and there's only 6 numbers to choose from on the die

Answer 2

Answer:    =0.375

Step-by-step explanation:

Actually we have to find the probability that both events will happened.

1st event the coin will be turned by a head P(head).

2nd event the number is greater than 2 , i.e. can be 3,4,5,6,7 or 8 P(a>2)

Both events  do not depend from each other. So the resulted probability

can be calculated multuplying probabilities P(head) and P(a>2) on each other. P(head, a>2)= P(head)*P(a>2)

P(head) =1/2=0.5 so the coin has 2 sides only one of them is head.

P(a>2)=6/8 so rolling the eight -sided doe 8 outcomes are possible and six of them 3,4,5,6,7 or 8 can give us the number that is bigger than 2.

P(a>2)=6/8=3/4=0.75

P(head, a>2)= P(head)*P(a>2)=0.5*0.75=0.375 ( rounding is not necessary, so we get exactle 3 digits after the point)