The distance measured between five successive crests of a wave motion executed by a photon of an electromagnetic radiation is 2.4cm.
1. Determine the wavelength in micrometers
2. what is the frequency of the photon
3. what is the energy possessed by the photon.​

Respuesta :

Answer:

1. λ = 0.48 cm = 4800 μm

2. υ = 6.25 x 10¹⁰ Hz

3. E = 4.14 x 10⁻²³ J

Explanation:

1.

Since, the wavelength is defined as the distance between two consecutive or successive crests or troughs. Therefore, in this case the wavelength will be equal to:

Wavelength = λ = Distance between 5 successive crests/5

λ = 2.4 cm/5

λ = 0.48 cm = 4800 μm

2.

The frequency of photon can be given as:

υ = c/λ

where,

υ = frequency of photon = ?

c = speed of light = 3 x 10⁸ m/s

λ = wavelength = 0.48 cm = 0.0048 m

Therefore,

υ = (3 x 10⁸ m/s)/(0.0048 m)

υ = 6.25 x 10¹⁰ Hz

3.

Now, the energy of photon is given as:

E = hυ

where,

E = Energy = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

Therefore,

E = (6.626 x 10⁻³⁴ J.s)(6.25 x 10¹⁰ Hz)

E = 4.14 x 10⁻²³ J

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