Answer:
The answer is option 2.
Step-by-step explanation:
First, you have to find the length of CD using Tangent Rule, tanθ = opposite/adjacent:
[tex] \tan(θ) = \frac{oppo.}{adj.} [/tex]
[tex]let \: θ = 48[/tex]
[tex]let \: oppo. = cd[/tex]
[tex]let \: adj. = ad = 110[/tex]
[tex] \tan(48) = \frac{cd}{110} [/tex]
[tex]cd = 110 \tan(48)[/tex]
[tex]cd = 122.17 \: feet[/tex]
Next, you have to find the length of BC using Sine Rule:
[tex] \sin(θ) = \frac{oppo.}{hypo.} [/tex]
[tex]let \: θ = 65[/tex]
[tex]let \: oppo. = cd = 122.17[/tex]
[tex]let \: hypo. = bc[/tex]
[tex] \sin(65) = \frac{122.17}{bc} [/tex]
[tex]bc = \frac{122.17}{ \sin(65) } [/tex]
[tex]bc = 134.8 \: feet \: (near.tenth)[/tex]
