Please help me with this question with full solutions!!!

Answer: Choice C
x/w and z/(y+v)
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Explanation:
All answer choices have that first fraction with a denominator of w. This implies that AB = w is the hypotenuse. This only applies to triangle ABD.
Focus on triangle ABD. It has an opposite leg of AD = x, when the reference angle is ABD (or angle B for short).
So we can say sin(ABD) = opposite/hypotenuse = AD/AB = x/w
x/w is one of the answers
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Also note how y+v is the same for each denominator in the second fraction. y+v is the hypotenuse of triangle ABC. When the reference angle is ABD (aka angle ABC), the opposite side of this same triangle is AX = z
Therefore,
sin(ABD) = sin(ABC) = opp/hyp = AC/BC = z/(y+v)
z/(y+v) is the other answer
Side note: triangle ACD is not used at all.
Answer:
[tex]\frac{x}{w}, \: \frac{z}{y+v}[/tex]
Step-by-step explanation:
sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]
Let’s take triangle ABD, where w is the hypotenuse.
sin ∠ABD = [tex]\frac{x}{w}[/tex]
Let’s take triangle ABC (whole triangle), where y + v is the hypotenuse.
sin ∠ABD = [tex]\frac{z}{y+v}[/tex]