Answer:
Enthalpy change = -98.6kJ
Explanation:
Based on the reaction:
2SO₂(g) + O₂(g) ⟶ 2SO₃(g), △H = -198 kJ
When 2 moles of SO₂ (Molar mass: 64.066g/mol) reacts with 1 mole of oxygen, enthalpy change is -198kJ
To know enthalpy change of 58.0g of SO₂ with excess oxygen we need to calculate moles of SO₂ thus:
58.0g SO₂ ₓ (1mol / 64.066g) = 0.905 moles SO₂
If 2 moles of SO₂ produce an enthalpy change of -198kJ, 0.905 moles SO₂ will produce:
0.905 moles SO₂ ₓ (-198kJ / 2 moles SO₂) =
Enthalpy change = -98.6kJ
