The main triangular sail on a sailboat is 25 feet tall and 10 feet wide at the bottom. If the sides of another sail are proportional to the main sail, and the bottom of this sail is 8 feet wide, how tall is it?

Answer:
Step-by-step explanation:
Here,,
Sides of two sail are proportional.
Let the height be 'x'
Now,
[tex] \frac{a1}{b1} = \frac{a2}{b2} [/tex]
plug the values
[tex] \frac{25}{10} = \frac{x}{8} [/tex]
Apply cross product property
[tex]10x = 25 \times 8[/tex]
Multiply the numbers
[tex]10x = 200[/tex]
Divide both sides of the equation by 10
[tex] \frac{10x}{10} = \frac{200}{10} [/tex]
Calculate
[tex]x = 20 \: ft[/tex]
Hope this helps...
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