Question

The value of y varies inversely as the square of x, and y = 16, when x = 3.
Find the value of 2 when y = 1 ​

Answer 1

Answer:

The answer is

12

Step-by-step explanation:

The above variation is written as

$y = \frac{k}{ {x}^{2} }$

where k is the constant of variation

when y = 16

x = 3

k = yx²

k = 16(3)²

k = 16 × 9

k = 144

The formula for the variation is

$y = \frac{144}{ {x}^{2} }$

when y = 1

We have

$1 = \frac{144}{ {x}^{2} }$

Cross multiply

x² = 144

Find the square root of both sides

x = √144

x = 12

Hope this helps you