Respuesta :
Answer:
Remaining amount of the element = 31.5 mg
Step-by-step explanation:
Half life of radioactive Iodine is [tex](T_{\frac{1}{2}})[/tex] = 60 days
Formula to get the remaining element after t days is,
[tex]N=N_0(e)^{\lambda.t}[/tex]
Where [tex]\lambda[/tex] = decay constant of the radioactive element
t = duration of the decay (in days)
[tex]N_0[/tex] = Initial amount of the element
N = final amount after decay
For half life period 't' = 60 days
[tex]\frac{N_0}{2}=N_0(e)^{\lambda\times 60}[/tex]
[tex]e^{60\lambda}=0.5[/tex]
[tex]ln(e^{60\lambda})=ln(0.5)[/tex]
[tex]60\lambda =-0.069315[/tex]
[tex]\lambda=-0.0115524[/tex]
Remaining amount of the element after 40 hours,
N = [tex]50(e^{40\lambda} )[/tex]
= [tex]50(e)^{-(0.0115524)\times 40}[/tex]
= 50(0.62996)
= 31.49
≈ 31.5 mg
Therefore, remaining amount of the element after 40 days is 31.5 mg.
Answer:
In 40 days, there would be approximately 31.5 mg remaining.
Step-by-step explanation:
