Question

Solve for x −ax + 2b > 8

Answer 1

Answer:

x < -( 8-2b) /a  a > 0

Step-by-step explanation:

−ax + 2b > 8

Subtract 2b from each side

−ax + 2b-2b > 8-2b

-ax > 8 -2b

Divide each side by -a, remembering to flip the inequality ( assuming a>0)

-ax/-a < ( 8-2b) /-a

x < -( 8-2b) /a  a > 0

Answer 2

Answer: $x<\frac{-8+2b}{a}$

                  $a>0$

Step-by-step explanation:

$-ax+2b>8$

$\mathrm{Subtract\:}2b\mathrm{\:from\:both\:sides}$

$-ax>8-2b$

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}$

$\left(-ax\right)\left(-1\right)<8\left(-1\right)-2b\left(-1\right)$

$ax<-8+2b$

$\mathrm{Divide\:both\:sides\:by\:}a$

$\frac{ax}{a}<-\frac{8}{a}+\frac{2b}{a};\quad \:a>0$

$x<\frac{-8+2b}{a};\quad \:a>0$