Respuesta :

Answer:

[tex]\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n[/tex]

Step-by-step explanation:

Given expression : [tex]\sum_{n=3}^{20}(n(n+1))[/tex]

Solving further :

[tex]\Rightarrow \sum_{n=3}^{20}(n^2+n)[/tex]

[tex]\Rightarrow \sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n[/tex]

So, [tex]\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n[/tex]

So, The given expression is equivalent to Option A

So, Option A is the answer

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