Find attached to this answer the diagram of the Quadrilateral
Question:
If ABCD is a parallelogram, AD = 14, EC = 11, m∠ABC = 64°, m∠DAC = 71°, and m∠BDC = 25, find each measure.
a) BC =
b) AC =
c) m∠DAB =
d) m∠ABD =
e) m∠ACD =
f) m∠ADB =
Answer:
a) BC = 11
b) AC = 22
c) m∠DAB = 116°
d) m∠ABD = 39°
e) m∠ACD = 45°
f) m∠ADB = 25°
Step-by-step explanation:
a) BC
In the question above, EC = 11
We can see that EC and BC are equal sides of a diagonal line that has been divided into two equal parts in a Quadrilateral.
Hence, In a quadrilateral ABCD,
EC = BC
Hence BC = 11
b) AC
AC is one of the diagonal lines that divided parallelogram ABCD
AC = BC + EC
AC = 11 + 11
AC = 22
c) m∠DAB
m∠ABC = 64°
m∠ADC = 64°
For the two angles above, a diagonal bisects through those angles.
Also the sum of angles in a triangle = 180°
Hence,
180° = 1/2m∠ABC + 1/2m∠ADC +
m∠DAB
m∠DAB = 180° - ( 1/2 (64) + 1/2(64))
m∠DAB = 180 ° - 64°
m∠DAB = 116°
d) m∠ABD
Since,
m∠ABC = 64° and m∠BDC = 25
m∠ABC = m∠BDC + m∠ABD
64 = 25+ m∠ABD
m∠ABD = 64° - 25°
m∠ABD = 39°
e) m∠ACD
In the above question,
m∠ABC = 64°,
m∠ADC = m∠ABC, this is because, opposite angles in a quadrilateral are congruent and equal to each other.
Hence, m∠ADC = 64°
m∠DAC = 71°,
In a triangle , all the angles in a triangle = 180°
Hence,
180° = m∠DAC + m∠ADC + m∠ACD
180° = 71° + 64 ° + m∠ACD
m∠ACD = 180° -(71 + 64)°
m∠ACD = 180° - 135°
m∠ACD = 45°
f) m∠ADB
Since
m∠DAB = 116°
m∠ABD = 39°
The sum of angles in a triangle = 180°
180° = m∠ABD + m∠DAB + m∠ADB
180° = 39 ° + 116° + m∠ADB
m∠ADB = 180° - ( 116 + 39)°
m∠ADB = 25 °
a) BC = 11
b) AC = 22
c) m∠DAB = 116°
d) m∠ABD = 39°
e) m∠ACD = 45°
f) m∠ADB = 25°
Given : AD=14 , EC=11, m∠ABC= 64°, m∠DAC=71° and m∠BDC=25°
To find: BC =? , AC =? , m∠DAB =?, m∠ABD =? ,m∠ACD =? ,m∠ADB =?
Consider the figure given below ABCD is a parallelogram
To find a) BC
Given, EC = 11
As seen in figure that EC and BC are equal sides of a diagonal line that has been divided into two equal parts in a Parallelogram.
Hence, In a Parallelogram ABCD,
EC = BC
Hence BC = 11
To find b) AC
AC is one of the diagonal lines that divided parallelogram ABCD
AC = BC + EC
AC = 11 + 11
AC = 22
To find c) m∠DAB
Given, m∠ABC = 64°
m∠ADC = 64°
(For the two angles above, a diagonal bisects through those angles)
Also From Angle sum property;
Hence,
180° = 1/2m∠ABC + 1/2m∠ADC + m∠DAB
m∠DAB = 180° - ( 1/2 (64) + 1/2(64))
m∠DAB = 180 ° - 64°
m∠DAB = 116°
To find d) m∠ABD
Since,
m∠ABC = 64° and m∠BDC = 25
m∠ABC = m∠BDC + m∠ABD
64 = 25+ m∠ABD
m∠ABD = 64° - 25°
m∠ABD = 39°
To find e) m∠ACD
Given, m∠ABC = 64°;
m∠ADC = m∠ABC, this is because, opposite angles in a quadrilateral (here parallelogram) are congruent and equal to each other
Hence, m∠ADC = 64°
m∠DAC = 71°,
In a triangle , all the angles in a triangle = 180°(Angle sum property)
Hence,
180° = m∠DAC + m∠ADC + m∠ACD
180° = 71° + 64 ° + m∠ACD
m∠ACD = 180° - (71 + 64)°
m∠ACD = 180° - 135°
m∠ACD = 45°
To find f) m∠ADB
Since ,m∠DAB = 116° and m∠ABD = 39°
From Angle sum property;
180° = m∠ABD + m∠DAB + m∠ADB
180° = 39 ° + 116° + m∠ADB
m∠ADB = 180° - ( 116 + 39)°
m∠ADB = 25 °
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