Answer:
y ≤ x + 3
y ≤ -2x + 3
Step-by-step explanation:
Graph attached shows two solid lines having equal y-intercepts as 3 units.
Since one line passes through two points (0, 3) and (-3, 0),
Slope of this line 'm' = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{3-0}{0+3}[/tex]
= 1
Let the equation of the this line is,
y = mx + b
where m = slope of the line
b = y-intercept
Therefore, equation of the line having slope = 1 and y-intercept = 3 units,
y = 1.x + 3
y = x + 3
Since, shaded region shown is on the left of the line y = x + 3
Therefore, y ≤ x + 3 will be the inequality with shaded area in green.
Slope of the second line passing through (0, 3) and (1.5, 0)
m' = [tex]\frac{3-0}{0-1.5}[/tex]
= -2
Therefore, equation of the second line will be,
y = (-2)x + 3
y = -2x + 3
Since shade area (In yellow) is below the given solid line, equation of the inequality will be,
y ≤ -2x + 3
