evaluate the function to find three points f(0)=

Answer:
f(0) = 0
Step-by-step explanation:
f(x) = -sqrt(x)
Let x= 0
f(0) = -sqrt(0)
f(0) = 0
Value of the given function [tex]f(x) = -\sqrt{x}[/tex] for [tex]f(0) = 0.[/tex]
" A function is defined as the relation between the given variable represents set of all input value should have one output each."
According to the question,
Given function,
[tex]f(x) = -\sqrt{x}[/tex]
Substitute the different values for 'x' for the given function we get,
[tex]x=1 , f(1) = -\sqrt{1}[/tex]
[tex]=-1[/tex]
[tex]x=4 , f(4) = -\sqrt{4}[/tex]
[tex]=-2[/tex]
[tex]x=0, f(0) = -\sqrt{0}[/tex]
[tex]=0[/tex]
Therefore, given relation is a function.
Hence, value of the given function [tex]f(x) = -\sqrt{x}[/tex] for [tex]f(0) = 0.[/tex]
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