Question

Drag the tiles to the correct box?

Answer 1

Answer:

1. (3,-1) and (5,4)  

$Distance\ = 5.39$    

2. (2,3) and (4,5)

$Distance\ = 2.83$

3. (-5,7) and (8,5)

$Distance = 13.15$

4. (-2,4) and (3,-1)

$Distance = 7.07$

Step-by-step explanation:

Given

The attached

Required

Calculate the distance between each points;

Distance between points is calculated using;

$d =\sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

1. (3,-1) and (5,4)

Here; $x_1 = 3; x_2 = 5; y_1 = -1; y_2 = 4$

Substitute these values in the formula above

$d =\sqrt{(3 - 5)^2 + (-1 - 4)^2}$

$d =\sqrt{- 2^2 + (-5^2)}$

$d =\sqrt{4 + 25}$

$d =\sqrt{29}$

$d = 5.39$    (Approximated)

2. (2,3) and (4,5)

Here; $x_1 = 2; x_2 = 4; y_1 = 3; y_2 = 5$

Substitute these values in the formula above

$d =\sqrt{(2 - 4)^2 + (3 - 5)^2}$

$d =\sqrt{- 2^2 + (-2^2)}$

$d =\sqrt{4 + 4}$

$d =\sqrt{8}$

$d = 2.83$    (Approximated)

3. (-5,7) and (8,5)

Here; $x_1 = -5; x_2 = 8; y_1 = 7; y_2 = 5$

Substitute these values in the formula above

$d =\sqrt{(-5 - 8)^2 + (7 - 5)^2}$

$d =\sqrt{- 13^2 + 2^2}$

$d =\sqrt{169 + 4}$

$d =\sqrt{173}$

$d = 13.15$    (Approximated)

4. (-2,4) and (3,-1)

Here; $x_1 = -2; x_2 = 3; y_1 = 4; y_2 = -1$

Substitute these values in the formula above

$d =\sqrt{(-2 - 3)^2 + (4 - (-1))^2}$

$d =\sqrt{- 5^2 + (4+1)^2}$

$d =\sqrt{- 5^2 + 5^2}$

$d =\sqrt{25 + 25}$

$d =\sqrt{50}$

$d = 7.07$    (Approximated)