Pls hellppp

Jennifer wants to visit 4 different cities A,B,C and D on her vacation. If she will visit them one at a time, and completly random, what is thr probabitly that she will visit them in the exact order ABCD or DCBA?​

Respuesta :

Answer: The probability that she will visit them in the exact order ABCD or DCBA =  [tex]\dfrac{1}{12}[/tex]

Step-by-step explanation:

Given: Jennifer wants to visit 4 different cities A,B,C and D on her vacation.

If she visits in an order , total such orders will be [tex]4![/tex] = 4 x 2 x 3 x 1 =24.

Since probability = [tex]\dfrac{\text{Favourable outcomes}}{\text{total outcomes}}[/tex]

In this case favorable outcomes ( ABCD ,  DCBA)=  2

Total outcomes = 24

Required probability = [tex]\dfrac{2}{24}=\dfrac{1}{12}[/tex]

Hence, the probability that she will visit them in the exact order ABCD or DCBA =  [tex]\dfrac{1}{12}[/tex]

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