the 1st one
third one
fourth one
the last one
each of the equation has one of the common factor out
Answer:
12(x+3y)
6(2x+6y)
4(3x+9y)
3(4x+12y)
Step-by-step explanation:
12(x+3y)= 12*x+12*3y= 12x+36y
6(2x+6y)= 6*2x+6*6y=12x+36y
4(3x+9y)=4*3x+4*9y=12x+36y
3(4x+12y)=3*4x+3*12y=12x+36y
hope it helps