Question

solve the simultaneous equation
y=x+3
y=7x+1
I'll mark you BRAINLIEST ​

Answer 1

Answer:

x = 1/3 , y = 10/3

Step-by-step explanation:

Solve the following system:

{y = x + 3 | (equation 1)

y = 7 x + 1 | (equation 2)

Express the system in standard form:

{-x + y = 3 | (equation 1)

-(7 x) + y = 1 | (equation 2)

Swap equation 1 with equation 2:

{-(7 x) + y = 1 | (equation 1)

-x + y = 3 | (equation 2)

Subtract 1/7 × (equation 1) from equation 2:

{-(7 x) + y = 1 | (equation 1)

0 x+(6 y)/7 = 20/7 | (equation 2)

Multiply equation 2 by 7/2:

{-(7 x) + y = 1 | (equation 1)

0 x+3 y = 10 | (equation 2)

Divide equation 2 by 3:

{-(7 x) + y = 1 | (equation 1)

0 x+y = 10/3 | (equation 2)

Subtract equation 2 from equation 1:

{-(7 x)+0 y = -7/3 | (equation 1)

0 x+y = 10/3 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 1/3 | (equation 1)

0 x+y = 10/3 | (equation 2)

Collect results:

Answer: {x = 1/3 , y = 10/3

Answer 2

Answer:

$\boxed{x=\frac{1}{3} }$

$\boxed{y=\frac{10}{3} }$

Step-by-step explanation:

$y=x+3\\y=7x+1$

Plug y as x+3 in the second equation.

$x+3=7x+1\\7x-x=3-1\\6x=2\\x=\frac{1}{3}$

Plug x as 1/3 in the second equation.

$y=7(\frac{1}{3} )+1\\y=\frac{7}{3}+1\\y=\frac{10}{3}$