Respuesta :

Answer:

[tex]x1 = - \frac{5}{2} [/tex]

[tex]x2 = \frac{4}{3} [/tex]

Step-by-step explanation:

[tex]18 {x}^{2} + 21x - 60 = 0[/tex]

Divide both sides of the equation by 3

[tex]6 {x}^{2} + 7x - 20 = 0[/tex]

Write 7x as a difference

[tex]6 {x}^{2} + 15x - 8x - 20 = 0[/tex]

Factor out 3x from the expression

[tex]3x(2x + 5) - 8x - 20 = 0[/tex]

Factor out -4 from the expression

[tex]3x(2x + 5) - 4(2x + 5) = 0[/tex]

Factor out 2x + 5 from the expression

[tex](2x + 5)(3x - 4) = 0[/tex]

When the product of factors equals 0 , at least one factor is 0

[tex]2x + 5 = 0[/tex]

[tex]3x - 4 = 0[/tex]

Solve the equation for X

[tex]2x + 5 = 0[/tex]

Move constant to R.H.S and change its sign

[tex]2x = 0 - 5[/tex]

Calculate the difference

[tex]2x = - 5[/tex]

Divide both sides of the equation by 2

[tex] \frac{2x}{2} = \frac{ - 5}{2} [/tex]

Calculate

[tex]x 1= - \frac{5}{2} [/tex]

Again,

[tex]3x - 4 = 0[/tex]

Move constant to RHS and change its sign

[tex]3x = 0 + 4[/tex]

Calculate the sum

[tex]3x = 4[/tex]

divide both sides of the equation by 3

[tex] \frac{3x}{3} = \frac{4}{3} [/tex]

Calculate

[tex]x 2= \frac{4}{3} [/tex]

Hope this helps..

Best regards!!

Answer:

39x+58

Step-by-step explanation:

18x 2+21x-60=0

pick the like terms together

18x+21x=39x

60-2=58

=39x+58

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