Respuesta :
Answer:
[tex]x1 = - \frac{5}{2} [/tex]
[tex]x2 = \frac{4}{3} [/tex]
Step-by-step explanation:
[tex]18 {x}^{2} + 21x - 60 = 0[/tex]
Divide both sides of the equation by 3
[tex]6 {x}^{2} + 7x - 20 = 0[/tex]
Write 7x as a difference
[tex]6 {x}^{2} + 15x - 8x - 20 = 0[/tex]
Factor out 3x from the expression
[tex]3x(2x + 5) - 8x - 20 = 0[/tex]
Factor out -4 from the expression
[tex]3x(2x + 5) - 4(2x + 5) = 0[/tex]
Factor out 2x + 5 from the expression
[tex](2x + 5)(3x - 4) = 0[/tex]
When the product of factors equals 0 , at least one factor is 0
[tex]2x + 5 = 0[/tex]
[tex]3x - 4 = 0[/tex]
Solve the equation for X
[tex]2x + 5 = 0[/tex]
Move constant to R.H.S and change its sign
[tex]2x = 0 - 5[/tex]
Calculate the difference
[tex]2x = - 5[/tex]
Divide both sides of the equation by 2
[tex] \frac{2x}{2} = \frac{ - 5}{2} [/tex]
Calculate
[tex]x 1= - \frac{5}{2} [/tex]
Again,
[tex]3x - 4 = 0[/tex]
Move constant to RHS and change its sign
[tex]3x = 0 + 4[/tex]
Calculate the sum
[tex]3x = 4[/tex]
divide both sides of the equation by 3
[tex] \frac{3x}{3} = \frac{4}{3} [/tex]
Calculate
[tex]x 2= \frac{4}{3} [/tex]
Hope this helps..
Best regards!!
Answer:
39x+58
Step-by-step explanation:
18x 2+21x-60=0
pick the like terms together
18x+21x=39x
60-2=58
=39x+58