A city park contain garden paths ( about 10% ) a lake ( about 15% ) and tennis courts. If the park is 2.4 ha and the tennis courts occupy a rectangular plot 60cm by 50cm how many hectares are left for garden?

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Answer:

As i understand it:

The total park is 2.4 ha

10% of that is paths and 15% of that is a lake.

So a 10% + 15% = 25% is taken.

So we have left a 75% of the park, this is:

Left = (75%/100%)2.4 ha = 0.75*2.4ha = 1.8 ha.

Now we also need to subtract the are of the tennis court.

The tennis court occupies a rectangular plot of 60m by 50m (you actually wrote cm here, but i guess it was a mistake, we can not have a tennis court of 60cm by 50cm)

So the area of the tennis court is:

A = 60m*50m = 3,000 m^2

But we want to write it in ha

We know that:

1ha = 10,000m^2

then 3,000m^2 = (3,000/10,000) ha = 0.3 ha

Then the left area is:

L = 1.8 ha - 0.3ha = 1.5 ha.

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