Answer:
Step-by-step explanation:
Hello,
First of all we will take any real number x different from 0, -2, +2 as dividing by 0 is not allowed and then we can write
[tex]\dfrac{( - x - 2)}{x(x^2 - 4)}=-\dfrac{x+2}{x(x-2)(x+2)}=\large \boxed{ -\dfrac{1}{x(x-2)}}[/tex]
because we know that
[tex]x^2-4=x^2-2^2=(x-2)(x+2)[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you