A brick of mass M has been placed on a rubber cushion of mass m. Together they are sliding to the right at constant velocity on an ice-covered parking lot. (a) Draw a free-body diagram of the brick and identify each force acting on it. (b) Draw a free-body diagram of the cushion and identify each force acting on it. (c) Identify all of the action–reaction pairs of forces in the brick–cushion–planet system.

Respuesta :

A) The free-body diagram of the forces acting on the brick is attached.

B) The free-body diagram of the forces acting on the rubber cushion is attached.

C) The action and reaction forces of the entire brick–cushion–planet system has been enumerated below.

A) The brick has a Mass M placed on top of a rubber cushion of mass m.

This means that there will be a normal force acting acting upwards on the brick and also a gravitational force acting downward. These forces are denoted as;

Normal force of rubber cushion acting on brick = [tex]n_{cb}[/tex]

Gravitational force acting on brick = Mg

Find attached the free body diagram.

B) The forces acting on the cushion will be;

Normal force of parking lot pavement on rubber cushion  = [tex]n_{pc}[/tex]

Gravitational force of earth acting on cushion = mg

Force of brick acting on the rubber cushion = [tex]F_{bc}[/tex]

C)  The action pairs of forces are;

i) Force; Normal force of rubber cushion acting on brick  = [tex]n_{cb}[/tex]

Reaction Force; Force of brick acting on the rubber cushion = [tex]F_{bc}[/tex]

ii) Action Force; Gravitational force acting on brick = Mg

Reaction; Gravitational force of brick acting on the earth

iii) Action Force; Normal force of parking lot pavement on rubber cushion = [tex]n_{pc}[/tex]

Reaction; Force of rubber cushion on parking lot pavement

iv) Action Force; Gravitational force of earth acting on rubber cushion = mg

Reaction Force; Gravitational force of rubber cushion on the earth.

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