Question

The gradient of a straight line that passes
through the point (-3,2) and (-4,k) is - 2
Find the value of k.​

Answer 1

Answer:

k=4

Step-by-step explanation:

We can use the slope formula

m = (y2-y1)/(x2-x1)

-2 = (k-2)/(-4 - -3)

-2 = (k-2)/(-4+3)

-2 = (k-2)/ ( -1)

Multiply by -1

-2 * -1 =  (k-2)/ ( -1) * -1

2 = k-2

Add 2 to each side

2+2 = k-2+2

4 =k