Question

Which equation shows a=bc^2+d solved for c

Answer 1

Answer:

$\large \boxed{c=\pm \sqrt{\dfrac{a-d}{b}}}$

Step-by-step explanation:

Hello,

$a=bc^2+d \\ \\ <=> a-d=bc^2+d-d=bc^2 \ \text{ subtract d }\\ \\ <=> c^2=\dfrac{a-d}{b} \ \text{ divide by b, assuming b is different from 0}\\ \\<=>\large \boxed{c=\pm \sqrt{\dfrac{a-d}{b}}} \ \ \text{ take the root of both parts}$

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