Answer:
[tex]\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64[/tex]
Step-by-step explanation:
As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:
[tex]\theta=3.7\\\\and\\\\\theta=5.7[/tex]
So, it's useful to solve the equation too, in order to verify the result:
[tex]-2sin(\theta)=1.2\\\\sin(\theta)=-\frac{3}{5}[/tex]
Taking the inverse sine of both sides:
[tex]\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64[/tex]
Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:
[tex]\theta\approx 3.785\\\\\theta \approx 5.64[/tex]