Respuesta :
Answer:
( 0 < y < 23 / 6 ) mins
Step-by-step explanation:
Solution:-
We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.
The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:
( 0 < x < 4 ) minutes
Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:
[tex]10 s * \frac{min}{60 s} = \frac{1}{6} min[/tex]
The time taken by Jo Anne to complete her speech in English class can be represented as:
y = x - 1/6
Using the range of time that Jo Anne could take in delivering her speech in the class would be:
0 < x < 4
0 - 1/6 < y < 4 - 1/6
-1/6 < y < 23 / 6
Since time can not be less than zero. We correct the lower limit to " 0 " as follows:
( 0 < y < 23 / 6 ) mins
The possible times for her speech of her at school vary between 0 and 3:50 minutes.
Since Jo Anne needs to do a speech in her English class that can't be more than 4 minutes long, and she timed herself when she practiced last night and was within the time limit, and in class, her speech was 10 seconds less than the one that she did at home, to determine what are the possible times for her speech at school the following calculation must be performed:
- If she in her house was within the time limit, at most her speech had a duration of 4 minutes, with which the maximum limit here is 3 minutes and 50 seconds.
- Therefore, the possible times for her speech of her at school vary between 0 and 3:50 minutes.
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