Answer:
Ajay has 10 rupees and Ragu has 20 rupees.
Step-by-step explanation:
Let's say Ajay has a rupees, and Ragu has r rupees.
Ragu lends 5 rupees to Ajay.
r - 5 = a + 5
r = a + 10
Ajay lends 5 rupees to Ragu.
5(a - 5) = r + 5
5a - 25 = r + 5
r + 5 = 5a - 25
r = 5a - 30
5a - 30 = a + 10
4a = 40
a = 10 rupees
r = 5 * 10 - 30
r = 50 - 30
r = 20 rupees
Hope this helps!
Answer:
Ajay has 15 Rupees while Ragu has 45 Rupees
Step-by-step explanation:
I believe by " one five", you mean fifteen
Let the original amount that Ajay has be "a"
Let the original amount that Ragu has be "r"
If Ragu lends Ajay 15 rupees, Ragu will now have, (r - 15) while Ajay will have (a + 15)
Since both of them will have equal amount, r - 15 = a + 15
r = a + 30.............(1)
If Ajay lends Ragu 5 rupees, Ajay will have a - 5 while Ragu will have r + 5.
Since Ragu will now have 5 times the amount Ajay has, r + 5 = 5(a - 5)
r + 5 = 5a - 25
r = 5a - 30.............(2)
Equating equations (1) and (2):
a + 30 = 5a - 30
4a = 60
a = 15
Substitute a = 15 into equation (2)
r = 5(15) - 30
r = 75 - 30
r = 45
Ajay has 15 Rupees while Ragu has 45 Rupees
