Answer: B. H(t) = -6.9(t - 2.3)² + 112
Step-by-step explanation:
The vertex form of a quadratic equation is: y = a(x - h)² + k
where (h, k) is the vertex ⇒ k is the maximum height
the distance traveled is when y = 0 ⇒ [tex]x=\sqrt{\dfrac{-k}{a}}+h[/tex]
Given: H(t) = -7.1(t - 2.3)² + 98
maximum height (k) = 98 feet
distance traveled (x) = [tex]\sqrt{\dfrac{-98}{-7.1}}+2.3[/tex] = 6.02 seconds
A) H(t) = -7.5(t - 2.2)² + 112
maximum height (k) = 112 feet
distance traveled (x) = [tex]\sqrt{\dfrac{-112}{-7.5}}+2.2[/tex] = 6.06 seconds
B) H(t) = -6.9(t - 2.3)² + 112
maximum height (k) = 112 feet
distance traveled (x) = [tex]\sqrt{\dfrac{-112}{-6.9}}+2.3[/tex] = 6.33 seconds
C) H(t) = -6.9(t - 2.4)² + 95
maximum height (k) = 95 feet
This has a lower height than the given equation.
D) H(t) = -7.5(t - 2.3)² + 95
maximum height (k) = 95 feet
This has a lower height than the given equation.
Both options A and B travel higher and stay in the air longer than last year's winner, however option B stays in the air longer than option A.
