Question

If log3=0.4771 and log2=0.3010,Find the value of log12

Answer 1

Answer:

log 12 = 1.0761

Step-by-step explanation:

log 12

=log(3*2*2)

= log 3 +log 2+ log 2

=0.4771+0.3010+0.3010

=1.0761

Answer 2

Answer:

Log 12 = 1.0791

Step-by-step explanation:

=> log (12)

Prime Factorizing 12

=> log (2×2×3)

Using log rule : $log (a*b) = log a+logb$

=> Log 2 + log 2 + log 3

Given that log 2 = 0.3010 , log 3 = 0.4771

=> 0.3010 + 0.3010 + 0.4771

=> 1.0791