Respuesta :
Answer:
a) Cost
[tex]C(q) = 50+16q\\\\C(500)=50+16(500)=50+8,000=8,050[/tex]
b) Sales income
[tex]S(q)=20q\\\\S(500)=20\cdot 500 = 10,000[/tex]
c) Table of values
[tex]\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right][/tex]
d) Attached
e) Breakeven point = 12.5 sheets
f) Profit at 550 sheets = $1,950
Step-by-step explanation:
a) We have a fixed cost for the image, at $50.
We also have a variable cost of $16 a sheet.
The purchased quantity is 500 sheets.
Then, the cost function is:
[tex]C(q) = 50+16q\\\\C(500)=50+16(500)=50+8,000=8,050[/tex]
b) The price for each sheet is $20, so the income from sales are:
[tex]S(q)=20q\\\\S(500)=20\cdot 500 = 10,000[/tex]
c) Table of values
[tex]\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right][/tex]
d) Attached
e) The minimum number of sheets the group must sell so they don't lose any money is the breakeven point (BEP) and can be calculated making the income sales equal to the cost:
[tex]S(q)=C(q)\\\\20q=50+16q\\\\(20-16)q=50\\\\4q=50\\\\q=50/4=12.5[/tex]
f) This profit can be calculated as the difference between the sales income and the cost:
[tex]P(500)=S(500)-C(500)\\\\P(500)=20\cdot 500-(50+16\cdot 500)=10,000-8,050=1,950[/tex]

The given number of 500 sheets of stamps purchased at $16/sheet with
a plan to sell each sheet for $20 gives the following values;
(a) Cost, C = 50 + 16·q
(b) Income, R = 20·q
(c) Please find the included table of values and the attached graph
(e) Approximately 403 sheets
(f) $1,950
Which method can be used to derive the equations?
(a) The cost per sheet of stamp = $16/sheet
The cost to create the image = $50
Amount at which they plan to sell each sheet, P = $20
Therefore
- Cost of obtaining the stamps, C = 50 + 16·q
(b) The income from sale, R = Number of units sold × P
Which gives;
- R = 20·q
(c) The table of values are therefore;
C = 50 + 16·q
[tex]\begin{array}{|c|c|c|}q&C=50+16 \times q\\0&50\\1&66\\2&82\\3&98\\4&114\\5&130\\6&146\\7&162\\8&178\\9&194\\10&210\\11&226\\12&242\\13&258\\14&274\end{array}\right][/tex]
R = 20·q
[tex]\begin{array}{|c|c|c|}q&R = 20 \times q\\0&0\\1&20\\2&40\\3&60\\4&80\\5&100\\6&120\\7&140\\8&160\\9&180\\10&200\\11&220\\12&240\\13&260\\14&280\end{array}\right][/tex]
Please find attached the required graph created with MS Excel
e) The minimum number of sheets the group must sell is given as follows;
The cost of the sheets purchased = 50 + 16 × 500
Which gives;
At point of profitability; Income = Cost
50 + 16 × 500 = 20·[tex]q_{min}[/tex]
[tex]q_{min} = \dfrac{50 + 16 \times 500}{20} =402.5 \approx \mathbf{403}[/tex]
- The minimum number the sheets they must sell, [tex]q_{min}[/tex] ≈ 403 sheets
(f) The profit made by selling 500 sheets is; 20·q - (50 + 16·q)
Where;
q = 500
Which gives;
20 × 500 - (50 + 16 × 500) = 1,950
The profit made from selling 500 sheet = $1,950
Learn more about graphs of functions here:
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