weeskrsm
weeskrsm
26-07-2020
Mathematics
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evaluate sin^-1(sin5)
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Аноним
Аноним
26-07-2020
−π2≤sin−1x≤π2
3π2≤5≤2π
−π2≤5−2π≤0≤π2
sin(5–2π)=sin5
Thus, sin−1(sin5)=5−2π
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