Answer:
Question one
2121.76 km
Question two
(N30°E)
Step-by-step explanation:
The given information are;
The time the plane takes off = 10:15 a.m.
The direction of flight of the plane = S30E
The speed of flight of the plane = 700 km/h
Question one
The of flight at 1:45 p.m. - 10:15 a.m = 3.5 hours
The distance traveled South by the plane is the product of the y-component of the velocity and the time of travel of the plane
The y-component of the velocity = v×cos(θ) = 700 × cos(30) = 350·√3 km/h
The distance traveled = 350·√3 km/h × 3.5 = 2121.76 km
Question two
The compass bearing of the airport the plane is North 30° West (N30°E).
