Answer:
[tex]\theta=\frac{n\pi}{5}[/tex]
Step-by-step explanation:
You have the following function:
[tex]r=2sin5\theta[/tex] (1)
In order to find the zeros of the function you equal to zero the equation (1), and then you solve for θ:
[tex]2sin5\theta=0\\\\sin5\theta=0\\\\5\theta=sin^{-1}(0)=n\pi;\ \ \ \ n=0,1,2,3,..\\\\\theta=\frac{n\pi}{5}[/tex]
Then, there are infinite zeros for the function of the equation (1), because n has infinite positive integers values.
